Sam left City X for City W at 08 39. Pamela left City X for City C at the same time. At 11 39, they were 612 km apart. Both maintained a constant speed and reached their destination at the same time at 15 14.
- Find the distance between Cities A and C.
- If Pamela was 57 the speed of Sam, find Sam's speed.
(a)
Time taken for Sam and Pamela to travel 08 39 to 11 39 = 3 h
Time taken for Sam and Pamela to travel 08 39 to 15 14 = 6 h 35 min = 6
3560 h = 6
712 h
Distance travelled by Sam and Pamela in 1 hour
= 612 ÷ 3
= 204 km
Total distance
= 6
712 x 204
= 1343 km
(b)
Pamela's distance : Sam's distance
5 : 7
Pamela's speed : Sam's speed
5 : 7
12 u = 204 km
1 u = 204 ÷ 12 = 17 km
Sam's speed
= 7 u
= 7 x 17
= 119 km/h
Answer(s): (a) 1343 km; (b) 119km/h