Will left City T for City S at 06 41. Cathy left City T for City C at the same time. At 10 41, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 13 20.
- Find the distance between Cities A and C.
- If Cathy was 57 the speed of Will, find Will's speed.
(a)
Time taken for Will and Cathy to travel 06 41 to 10 41 = 4 h
Time taken for Will and Cathy to travel 06 41 to 13 20 = 6 h 39 min = 6
3960 h = 6
1320 h
Distance travelled by Will and Cathy in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 6
1320 x 180
= 1197 km
(b)
Cathy's distance : Will's distance
5 : 7
Cathy's speed : Will's speed
5 : 7
12 u = 180 km
1 u = 180 ÷ 12 = 15 km
Will's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1197 km; (b) 105km/h