Flynn left City U for City T at 07 50. Eva left City U for City C at the same time. At 10 50, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 14 42.
- Find the distance between Cities A and C.
- If Eva was 45 the speed of Flynn, find Flynn's speed.
(a)
Time taken for Flynn and Eva to travel 07 50 to 10 50 = 3 h
Time taken for Flynn and Eva to travel 07 50 to 14 42 = 6 h 52 min = 6
5260 h = 6
1315 h
Distance travelled by Flynn and Eva in 1 hour
= 540 ÷ 3
= 180 km
Total distance
= 6
1315 x 180
= 1236 km
(b)
Eva's distance : Flynn's distance
4 : 5
Eva's speed : Flynn's speed
4 : 5
9 u = 180 km
1 u = 180 ÷ 9 = 20 km
Flynn's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1236 km; (b) 100km/h