Jeremy left City N for City M at 07 43. Sabrina left City N for City C at the same time. At 10 43, they were 540 km apart. Both maintained a constant speed and reached their destination at the same time at 12 21.

1. Find the distance between Cities A and C.
2. If Sabrina was ⁵₇ the speed of Jeremy, find Jeremy's speed.

(a)
Time taken for Jeremy and Sabrina to travel 07 43 to 10 43 = 3 h
Time taken for Jeremy and Sabrina to travel 07 43 to 12 21 = 4 h 38 min = 4³⁸₆₀ h = 4¹⁹₃₀ h

Distance travelled by Jeremy and Sabrina in 1 hour
= 540 ÷ 3
= 180 km

Total distance
= 4¹⁹₃₀ x 180
= 834 km

(b)
Sabrina's distance : Jeremy's distance
5 : 7

Sabrina's speed : Jeremy's speed
5 : 7

12 u = 180 km
1 u = 180 ÷ 12 = 15 km

Jeremy's speed
= 7 u
= 7 x 15
= 105 km/h

Answer(s): (a) 834 km; (b) 105km/h