Henry left City V for City U at 09 49. Jean left City V for City C at the same time. At 13 49, they were 672 km apart. Both maintained a constant speed and reached their destination at the same time at 16 24.
- Find the distance between Cities A and C.
- If Jean was 35 the speed of Henry, find Henry's speed.
(a)
Time taken for Henry and Jean to travel 09 49 to 13 49 = 4 h
Time taken for Henry and Jean to travel 09 49 to 16 24 = 6 h 35 min = 6
3560 h = 6
712 h
Distance travelled by Henry and Jean in 1 hour
= 672 ÷ 4
= 168 km
Total distance
= 6
712 x 168
= 1106 km
(b)
Jean's distance : Henry's distance
3 : 5
Jean's speed : Henry's speed
3 : 5
8 u = 168 km
1 u = 168 ÷ 8 = 21 km
Henry's speed
= 5 u
= 5 x 21
= 105 km/h
Answer(s): (a) 1106 km; (b) 105km/h