Japheth left City Q for City P at 07 27. Shannon left City Q for City C at the same time. At 11 27, they were 720 km apart. Both maintained a constant speed and reached their destination at the same time at 14 21.
- Find the distance between Cities A and C.
- If Shannon was 57 the speed of Japheth, find Japheth's speed.
(a)
Time taken for Japheth and Shannon to travel 07 27 to 11 27 = 4 h
Time taken for Japheth and Shannon to travel 07 27 to 14 21 = 6 h 54 min = 6
5460 h = 6
910 h
Distance travelled by Japheth and Shannon in 1 hour
= 720 ÷ 4
= 180 km
Total distance
= 6
910 x 180
= 1242 km
(b)
Shannon's distance : Japheth's distance
5 : 7
Shannon's speed : Japheth's speed
5 : 7
12 u = 180 km
1 u = 180 ÷ 12 = 15 km
Japheth's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1242 km; (b) 105km/h