Ethan left City Q for City P at 09 20. Jaslyn left City Q for City C at the same time. At 11 20, they were 288 km apart. Both maintained a constant speed and reached their destination at the same time at 16 10.
- Find the distance between Cities A and C.
- If Jaslyn was 35 the speed of Ethan, find Ethan's speed.
(a)
Time taken for Ethan and Jaslyn to travel 09 20 to 11 20 = 2 h
Time taken for Ethan and Jaslyn to travel 09 20 to 16 10 = 6 h 50 min = 6
5060 h = 6
56 h
Distance travelled by Ethan and Jaslyn in 1 hour
= 288 ÷ 2
= 144 km
Total distance
= 6
56 x 144
= 984 km
(b)
Jaslyn's distance : Ethan's distance
3 : 5
Jaslyn's speed : Ethan's speed
3 : 5
8 u = 144 km
1 u = 144 ÷ 8 = 18 km
Ethan's speed
= 5 u
= 5 x 18
= 90 km/h
Answer(s): (a) 984 km; (b) 90km/h