Michael left City H for City G at 08 36. Fanny left City H for City C at the same time. At 10 36, they were 264 km apart. Both maintained a constant speed and reached their destination at the same time at 13 16.

1. Find the distance between Cities A and C.
2. If Fanny was ⁴₇ the speed of Michael, find Michael's speed.

(a)
Time taken for Michael and Fanny to travel 08 36 to 10 36 = 2 h
Time taken for Michael and Fanny to travel 08 36 to 13 16 = 4 h 40 min = 4⁴⁰₆₀ h = 4²₃ h

Distance travelled by Michael and Fanny in 1 hour
= 264 ÷ 2
= 132 km

Total distance
= 4²₃ x 132
= 616 km

(b)
Fanny's distance : Michael's distance
4 : 7

Fanny's speed : Michael's speed
4 : 7

11 u = 132 km
1 u = 132 ÷ 11 = 12 km

Michael's speed
= 7 u
= 7 x 12
= 84 km/h

Answer(s): (a) 616 km; (b) 84km/h