Jaslyn had an equal number of mangoes and peaches at first. She sold half of the peaches and bought another 28 mangoes. In the end, she had six times as many mangoes as peaches. Find the number of peaches she had at first.
| |
Mangoes |
Peaches |
| Before |
6 u - 28 |
2 u |
| Change |
+ 28 |
- 1 u |
| After |
6 u |
1 u |
The number of mangoes and peaches at first is the same.
6 u - 28 = 2 u
6 u - 2 u = 28
4 u = 28
1 u = 28 ÷ 4 = 7
Number of peaches that Jaslyn had at first
= 2 u
= 2 x 7
= 14
Answer(s): 14
