The figure is not drawn to scale. GKLN is a parallelogram, FGN and GHN are isosceles triangles. NL//PV and ∠LUV= 110°. FK is straight line.
- Find ∠FNG.
- Find ∠KHN.
(a)
∠LUV = 110°
∠NST = 110° (Corresponding angles)
∠RSN
= 180° - 110°
= 70° (Angles on a straight line)
∠FNG
= 180° - 70° - 70°
= 40° (Isosceles triangle)
(b)
∠RSN = ∠FGN = 70° (Corresponding angles)
∠NGH
= 180° - 70°
= 110° (Angles on a straight line)
∠GHT
= (180° - 110°) ÷ 2
= 35° (Isosceles triangle)
∠KHN
= 180° - 35°
= 145° (Angles on a straight line)
Answer(s): (a) 40°; (b) 145°
