A vendor paid a total of $2080 for some blazers and some sweaters. He paid $800 less for the blazers than the sweaters. Each blazer cost $13 less than each sweater. The number of blazers he bought was
58 of the number of sweaters bought.
- How much did he pay for all the blazers?
- How many blazers did he buy?
|
Blazers |
Sweaters |
Difference in cost |
Number of items in 1 set |
Number of sets |
5 |
8 |
|
|
Total cost |
$640 |
$1440 |
|
|
Cost of 1 set |
640 ÷ 5 = $128 |
1440 ÷ 8 = $180 |
180 - 128 = $52 |
|
Cost of each item |
1 u |
1 u + $13 |
$13 |
52 ÷ 13 = 4 |
(a)
Total amount = $2080
Total amount spent on blazers = (2080 - 800) ÷ 2 = $640
Total amount spent on sweaters = 640 + 800 = $1440
Amount that he paid for all the blazers = $640
(b)
5 sets of blazers = $640
8 sets of sweaters = $1440
1 set of blazers = 640 ÷ 5 = $128
1 set of sweaters = 1440 ÷ 8 = $180
Difference in the amount paid for each set of sweaters and blazers
= 180 - 128
= $52
The extra $52 is due to each sweater costing $13 more than each blazer.
Number of blazers in 1 set
= 52 ÷ 13
= 4
Number of blazers that he bought
= 5 sets of blazers
= 5 x 4
= 20
Answer(s): (a) $640; (b) 20