A seller paid a total of $1760 for some vests and some jackets. He paid $880 less for the vests than the jackets. Each jacket cost $22 more than each vest. The number of vests he bought was
45 of the number of jackets bought.
- How much did he pay for all the vests?
- How many vests did he buy?
|
Vests |
Jackets |
Difference in cost |
Number of items in 1 set |
Number of sets |
4 |
5 |
|
|
Total cost |
$440 |
$1320 |
|
|
Cost of 1 set |
440 ÷ 4 = $110 |
1320 ÷ 5 = $264 |
264 - 110 = $154 |
|
Cost of each item |
1 u |
1 u + $22 |
$22 |
154 ÷ 22 = 7 |
(a)
Total amount = $1760
Total amount spent on vests = (1760 - 880) ÷ 2 = $440
Total amount spent on jackets = 440 + 880 = $1320
Amount that he paid for all the vests = $440
(b)
4 sets of vests = $440
5 sets of jackets = $1320
1 set of vests = 440 ÷ 4 = $110
1 set of jackets = 1320 ÷ 5 = $264
Difference in the amount paid for each set of jackets and vests
= 264 - 110
= $154
The extra $154 is due to each jacket costing $22 more than each vest.
Number of vests in 1 set
= 154 ÷ 22
= 7
Number of vests that he bought
= 4 sets of vests
= 4 x 7
= 28
Answer(s): (a) $440; (b) 28