A shop owner paid a total of $1350 for some blouses and some dresses. He paid $810 more for the dresses than the blouses. Each dress cost $25 more than each blouse. The number of blouses he bought was
23 of the number of dresses bought.
- How much did he pay for all the blouses?
- How many blouses did he buy?
|
Blouses |
Dresses |
Difference in cost |
Number of items in 1 set |
Number of sets |
2 |
3 |
|
|
Total cost |
$270 |
$1080 |
|
|
Cost of 1 set |
270 ÷ 2 = $135 |
1080 ÷ 3 = $360 |
360 - 135 = $225 |
|
Cost of each item |
1 u |
1 u + $25 |
$25 |
225 ÷ 25 = 9 |
(a)
Total amount = $1350
Total amount spent on blouses = (1350 - 810) ÷ 2 = $270
Total amount spent on dresses = 270 + 810 = $1080
Amount that he paid for all the blouses = $270
(b)
2 sets of blouses = $270
3 sets of dresses = $1080
1 set of blouses = 270 ÷ 2 = $135
1 set of dresses = 1080 ÷ 3 = $360
Difference in the amount paid for each set of dresses and blouses
= 360 - 135
= $225
The extra $225 is due to each dress costing $25 more than each blouse.
Number of blouses in 1 set
= 225 ÷ 25
= 9
Number of blouses that he bought
= 2 sets of blouses
= 2 x 9
= 18
Answer(s): (a) $270; (b) 18