A seller paid a total of $2520 for some coats and some blazers. He paid $840 more for the blazers than the coats. Each blazer cost $18 more than each coat. The number of coats he bought was ⁴₅ of the number of blazers bought.

1. How much did he pay for all the coats?
2. How many coats did he buy?

	Coats	Blazers	Difference in cost	Number of items in 1 set
Number of sets	4	5
Total cost	$840	$1680
Cost of 1 set	840 ÷ 4 = $210	1680 ÷ 5 = $336	336 - 210 = $126
Cost of each item	1 u	1 u + $18	$18	126 ÷ 18 = 7

(a)
Total amount = $2520
Total amount spent on coats = (2520 - 840) ÷ 2 = $840
Total amount spent on blazers = 840 + 840 = $1680

Amount that he paid for all the coats = $840

(b)
4 sets of coats = $840
5 sets of blazers = $1680

1 set of coats = 840 ÷ 4 = $210
1 set of blazers = 1680 ÷ 5 = $336

Difference in the amount paid for each set of blazers and coats
= 336 - 210
= $126

The extra $126 is due to each blazer costing $18 more than each coat.

Number of coats in 1 set
= 126 ÷ 18
= 7

Number of coats that he bought
= 4 sets of coats
= 4 x 7
= 28

Answer(s): (a) $840; (b) 28