A boutique owner paid a total of $1620 for some windbreakers and some dresses. He paid $1260 less for the windbreakers than the dresses. Each dress cost $27 more than each windbreaker. The number of windbreakers he bought was ⁴₅ of the number of dresses bought.

1. How much did he pay for all the windbreakers?
2. How many windbreakers did he buy?

	Windbreakers	Dresses	Difference in cost	Number of items in 1 set
Number of sets	4	5
Total cost	$180	$1440
Cost of 1 set	180 ÷ 4 = $45	1440 ÷ 5 = $288	288 - 45 = $243
Cost of each item	1 u	1 u + $27	$27	243 ÷ 27 = 9

(a)
Total amount = $1620
Total amount spent on windbreakers = (1620 - 1260) ÷ 2 = $180
Total amount spent on dresses = 180 + 1260 = $1440

Amount that he paid for all the windbreakers = $180

(b)
4 sets of windbreakers = $180
5 sets of dresses = $1440

1 set of windbreakers = 180 ÷ 4 = $45
1 set of dresses = 1440 ÷ 5 = $288

Difference in the amount paid for each set of dresses and windbreakers
= 288 - 45
= $243

The extra $243 is due to each dress costing $27 more than each windbreaker.

Number of windbreakers in 1 set
= 243 ÷ 27
= 9

Number of windbreakers that he bought
= 4 sets of windbreakers
= 4 x 9
= 36

Answer(s): (a) $180; (b) 36