A retailer paid a total of $462 for some blazers and some shirts. He paid $198 less for the blazers than the shirts. Each shirt cost $11 more than each blazer. The number of blazers he bought was ²₃ of the number of shirts bought.

1. How much did he pay for all the blazers?
2. How many blazers did he buy?

	Blazers	Shirts	Difference in cost	Number of items in 1 set
Number of sets	2	3
Total cost	$132	$330
Cost of 1 set	132 ÷ 2 = $66	330 ÷ 3 = $110	110 - 66 = $44
Cost of each item	1 u	1 u + $11	$11	44 ÷ 11 = 4

(a)
Total amount = $462
Total amount spent on blazers = (462 - 198) ÷ 2 = $132
Total amount spent on shirts = 132 + 198 = $330

Amount that he paid for all the blazers = $132

(b)
2 sets of blazers = $132
3 sets of shirts = $330

1 set of blazers = 132 ÷ 2 = $66
1 set of shirts = 330 ÷ 3 = $110

Difference in the amount paid for each set of shirts and blazers
= 110 - 66
= $44

The extra $44 is due to each shirt costing $11 more than each blazer.

Number of blazers in 1 set
= 44 ÷ 11
= 4

Number of blazers that he bought
= 2 sets of blazers
= 2 x 4
= 8

Answer(s): (a) $132; (b) 8