A vendor paid a total of $1440 for some dresses and some vests. He paid $576 less for the dresses than the vests. Each dress cost $20 less than each vest. The number of dresses he bought was
23 of the number of vests bought.
- How much did he pay for all the dresses?
- How many dresses did he buy?
|
Dresses |
Vests |
Difference in cost |
Number of items in 1 set |
Number of sets |
2 |
3 |
|
|
Total cost |
$432 |
$1008 |
|
|
Cost of 1 set |
432 ÷ 2 = $216 |
1008 ÷ 3 = $336 |
336 - 216 = $120 |
|
Cost of each item |
1 u |
1 u + $20 |
$20 |
120 ÷ 20 = 6 |
(a)
Total amount = $1440
Total amount spent on dresses = (1440 - 576) ÷ 2 = $432
Total amount spent on vests = 432 + 576 = $1008
Amount that he paid for all the dresses = $432
(b)
2 sets of dresses = $432
3 sets of vests = $1008
1 set of dresses = 432 ÷ 2 = $216
1 set of vests = 1008 ÷ 3 = $336
Difference in the amount paid for each set of vests and dresses
= 336 - 216
= $120
The extra $120 is due to each vest costing $20 more than each dress.
Number of dresses in 1 set
= 120 ÷ 20
= 6
Number of dresses that he bought
= 2 sets of dresses
= 2 x 6
= 12
Answer(s): (a) $432; (b) 12