A shop owner paid a total of $2080 for some dresses and some vests. He paid $800 less for the dresses than the vests. Each vest cost $13 more than each dress. The number of dresses he bought was
58 of the number of vests bought.
- How much did he pay for all the dresses?
- How many dresses did he buy?
|
Dresses |
Vests |
Difference in cost |
Number of items in 1 set |
Number of sets |
5 |
8 |
|
|
Total cost |
$640 |
$1440 |
|
|
Cost of 1 set |
640 ÷ 5 = $128 |
1440 ÷ 8 = $180 |
180 - 128 = $52 |
|
Cost of each item |
1 u |
1 u + $13 |
$13 |
52 ÷ 13 = 4 |
(a)
Total amount = $2080
Total amount spent on dresses = (2080 - 800) ÷ 2 = $640
Total amount spent on vests = 640 + 800 = $1440
Amount that he paid for all the dresses = $640
(b)
5 sets of dresses = $640
8 sets of vests = $1440
1 set of dresses = 640 ÷ 5 = $128
1 set of vests = 1440 ÷ 8 = $180
Difference in the amount paid for each set of vests and dresses
= 180 - 128
= $52
The extra $52 is due to each vest costing $13 more than each dress.
Number of dresses in 1 set
= 52 ÷ 13
= 4
Number of dresses that he bought
= 5 sets of dresses
= 5 x 4
= 20
Answer(s): (a) $640; (b) 20