A seller paid a total of $1960 for some windbreakers and some coats. He paid $840 more for the coats than the windbreakers. Each coat cost $21 more than each windbreaker. The number of windbreakers he bought was ⁵₈ of the number of coats bought.

1. How much did he pay for all the windbreakers?
2. How many windbreakers did he buy?

	Windbreakers	Coats	Difference in cost	Number of items in 1 set
Number of sets	5	8
Total cost	$560	$1400
Cost of 1 set	560 ÷ 5 = $112	1400 ÷ 8 = $175	175 - 112 = $63
Cost of each item	1 u	1 u + $21	$21	63 ÷ 21 = 3

(a)
Total amount = $1960
Total amount spent on windbreakers = (1960 - 840) ÷ 2 = $560
Total amount spent on coats = 560 + 840 = $1400

Amount that he paid for all the windbreakers = $560

(b)
5 sets of windbreakers = $560
8 sets of coats = $1400

1 set of windbreakers = 560 ÷ 5 = $112
1 set of coats = 1400 ÷ 8 = $175

Difference in the amount paid for each set of coats and windbreakers
= 175 - 112
= $63

The extra $63 is due to each coat costing $21 more than each windbreaker.

Number of windbreakers in 1 set
= 63 ÷ 21
= 3

Number of windbreakers that he bought
= 5 sets of windbreakers
= 5 x 3
= 15

Answer(s): (a) $560; (b) 15