A vendor paid a total of $1440 for some dresses and some jackets. He paid $640 more for the jackets than the dresses. Each jacket cost $18 more than each dress. The number of dresses he bought was
45 of the number of jackets bought.
- How much did he pay for all the dresses?
- How many dresses did he buy?
|
Dresses |
Jackets |
Difference in cost |
Number of items in 1 set |
Number of sets |
4 |
5 |
|
|
Total cost |
$400 |
$1040 |
|
|
Cost of 1 set |
400 ÷ 4 = $100 |
1040 ÷ 5 = $208 |
208 - 100 = $108 |
|
Cost of each item |
1 u |
1 u + $18 |
$18 |
108 ÷ 18 = 6 |
(a)
Total amount = $1440
Total amount spent on dresses = (1440 - 640) ÷ 2 = $400
Total amount spent on jackets = 400 + 640 = $1040
Amount that he paid for all the dresses = $400
(b)
4 sets of dresses = $400
5 sets of jackets = $1040
1 set of dresses = 400 ÷ 4 = $100
1 set of jackets = 1040 ÷ 5 = $208
Difference in the amount paid for each set of jackets and dresses
= 208 - 100
= $108
The extra $108 is due to each jacket costing $18 more than each dress.
Number of dresses in 1 set
= 108 ÷ 18
= 6
Number of dresses that he bought
= 4 sets of dresses
= 4 x 6
= 24
Answer(s): (a) $400; (b) 24