A shop owner paid a total of $1920 for some sweaters and some blazers. He paid $720 more for the blazers than the sweaters. Each blazer cost $16 more than each sweater. The number of sweaters he bought was ³₅ of the number of blazers bought.

1. How much did he pay for all the sweaters?
2. How many sweaters did he buy?

	Sweaters	Blazers	Difference in cost	Number of items in 1 set
Number of sets	3	5
Total cost	$600	$1320
Cost of 1 set	600 ÷ 3 = $200	1320 ÷ 5 = $264	264 - 200 = $64
Cost of each item	1 u	1 u + $16	$16	64 ÷ 16 = 4

(a)
Total amount = $1920
Total amount spent on sweaters = (1920 - 720) ÷ 2 = $600
Total amount spent on blazers = 600 + 720 = $1320

Amount that he paid for all the sweaters = $600

(b)
3 sets of sweaters = $600
5 sets of blazers = $1320

1 set of sweaters = 600 ÷ 3 = $200
1 set of blazers = 1320 ÷ 5 = $264

Difference in the amount paid for each set of blazers and sweaters
= 264 - 200
= $64

The extra $64 is due to each blazer costing $16 more than each sweater.

Number of sweaters in 1 set
= 64 ÷ 16
= 4

Number of sweaters that he bought
= 3 sets of sweaters
= 3 x 4
= 12

Answer(s): (a) $600; (b) 12