A boutique owner paid a total of $2160 for some windbreakers and some skirts. He paid $560 more for the skirts than the windbreakers. Each skirt cost $9 more than each windbreaker. The number of windbreakers he bought was
45 of the number of skirts bought.
- How much did he pay for all the windbreakers?
- How many windbreakers did he buy?
|
Windbreakers |
Skirts |
Difference in cost |
Number of items in 1 set |
Number of sets |
4 |
5 |
|
|
Total cost |
$800 |
$1360 |
|
|
Cost of 1 set |
800 ÷ 4 = $200 |
1360 ÷ 5 = $272 |
272 - 200 = $72 |
|
Cost of each item |
1 u |
1 u + $9 |
$9 |
72 ÷ 9 = 8 |
(a)
Total amount = $2160
Total amount spent on windbreakers = (2160 - 560) ÷ 2 = $800
Total amount spent on skirts = 800 + 560 = $1360
Amount that he paid for all the windbreakers = $800
(b)
4 sets of windbreakers = $800
5 sets of skirts = $1360
1 set of windbreakers = 800 ÷ 4 = $200
1 set of skirts = 1360 ÷ 5 = $272
Difference in the amount paid for each set of skirts and windbreakers
= 272 - 200
= $72
The extra $72 is due to each skirt costing $9 more than each windbreaker.
Number of windbreakers in 1 set
= 72 ÷ 9
= 8
Number of windbreakers that he bought
= 4 sets of windbreakers
= 4 x 8
= 32
Answer(s): (a) $800; (b) 32