A store owner paid a total of $3120 for some jackets and some sweaters. He paid $720 less for the jackets than the sweaters. Each jacket cost $12 less than each sweater. The number of jackets he bought was
45 of the number of sweaters bought.
- How much did he pay for all the jackets?
- How many jackets did he buy?
|
Jackets |
Sweaters |
Difference in cost |
Number of items in 1 set |
Number of sets |
4 |
5 |
|
|
Total cost |
$1200 |
$1920 |
|
|
Cost of 1 set |
1200 ÷ 4 = $300 |
1920 ÷ 5 = $384 |
384 - 300 = $84 |
|
Cost of each item |
1 u |
1 u + $12 |
$12 |
84 ÷ 12 = 7 |
(a)
Total amount = $3120
Total amount spent on jackets = (3120 - 720) ÷ 2 = $1200
Total amount spent on sweaters = 1200 + 720 = $1920
Amount that he paid for all the jackets = $1200
(b)
4 sets of jackets = $1200
5 sets of sweaters = $1920
1 set of jackets = 1200 ÷ 4 = $300
1 set of sweaters = 1920 ÷ 5 = $384
Difference in the amount paid for each set of sweaters and jackets
= 384 - 300
= $84
The extra $84 is due to each sweater costing $12 more than each jacket.
Number of jackets in 1 set
= 84 ÷ 12
= 7
Number of jackets that he bought
= 4 sets of jackets
= 4 x 7
= 28
Answer(s): (a) $1200; (b) 28