There were some chikoos, oranges and pears. The number of chikoos was two times the number of oranges. The total number of chikoos and oranges was one-quarter of the number of pears. There were 180 fruits altogether. All the pears were sold at 8 for $10. How much money was collected from the sale of the pears?
Number of oranges = 1 u
Number of chikoos = 2 u

Total number of oranges and chikoos
= 1 u + 2 u
= 3 u

Number of pears
= 4 x 3 u
= 12 u

Total number of fruits
= 1 u + 2 u + 12 u
= 15 u

15 u = 180

1 u = 180 ÷ 15 = 12

Number of pears sold
= 12 u
= 12 x 12
= 144

Number of sets of 8 pears
= 144 ÷ 8
= 18

Amount collected from the sale of pears
= 18 x 10
= $180

Answer(s): $180