Four children made the following statements.
Wyatt : The average of Aaron's mass and my mass is 49 kg.
Sofia : I am the heaviest.
Aaron : Ethan is 2 kg lighter than Sofia.
Ethan : Our masses are in consecutive order.

What is the total mass of Wyatt, Sofia and Aaron ?
Order of the mass of 4 children:
_____ , Ethan, _____ , Sofia (Heaviest)

Total mass of Wyatt and Aaron 
= 2 x 49
= 98 kg

For Wyatt and Aaron,
Mass of the lighter one = 1 u
Mass of the heavier one = 1 u + 2

Total mass of Wyatt and Aaron
= 1 u + 1 u + 2
= 2 u + 2

2 u + 2 = 98 
2 u = 98 - 2
2 u = 96

1 u = 96 ÷ 2 = 48

The mass of the four children in consecutive order is 48, 49, 50 and 51.

Total mass of Wyatt, Sofia and Aaron
= 48 + 50 + 51
= 149

Answer(s): 149 kg