Four children made the following statements.
Emma : Mason is 2 kg heavier than Mia.
Mia : Our masses are in consecutive order.
Jeremiah : The average of Emma's mass and my mass is 40 kg.
Mason : I am the heaviest.

What is the total mass of Jeremiah, Mason and Emma ?
Order of the mass of 4 children:
_____ , Mia, _____ , Mason (Heaviest)

Total mass of Jeremiah and Emma
= 2 x 40
= 80 kg

For Jeremiah and Emma,
Mass of the lighter one = 1 u
Mass of the heavier one = 1 u + 2

Total mass of Jeremiah and Emma
= 1 u + 1 u + 2
= 2 u + 2

2 u + 2 = 80
2 u = 80 - 2
2 u = 78

1 u = 78 ÷ 2 = 39

The mass of the four children in consecutive order is 39, 40, 41 and 42.

Total mass of Jeremiah, Mason and Emma
= 39 + 41 + 42
= 122

Answer(s): 122 kg