The prices of two fruits sold at a supermarket is shown.

Fruit	Price
Chikoos	5 kg for $11
Lemons	4 kg for $6

1. Michael bought an equal mass of chikoos and lemons and spent $98 more on chikoos than on lemons. What was the total mass of fruits that Michael bought?
2. Yen spent an equal amount of money on chikoos and lemons. In terms of their masses, what was the ratio of chikoos to the ratio of lemons Yen bought?

(a)
LCM of 5 and 4 = 20

One set = 20 kg of chikoos and 20 kg of lemons

Number of sets of 5 kg of chikoos
= 20 ÷ 5
= 4

Number of sets of 4 kg of lemons
= 20 ÷ 4
= 5

Difference in price of chikoos and lemons in one set
= 4 x 11 - 5 x 6
= 44 - 30
= $14

Number of sets
= 98 ÷ 14
= 7

Mass of chikoos and lemons in one set
= 20 + 20
= 40 kg

Total mass of fruits bought
= 7 x 40
= 280 kg

(b)
LCM of 11 and 6 = 66

Number of sets of 5 kg of chikoos to be bought with $66
= 66 ÷ 11
= 6

Mass of 6 sets of 5 kg of chikoos
= 6 x 5
= 30 kg

Number of sets of 4 kg of chikoos to be bought with $66
= 66 ÷ 6
= 11

Mass of 11 sets of 4 kg of lemons
= 11 x 4
= 44 kg

Mass of chikoos : Mass of lemons 
30 : 44 _(÷2)
15 : 22

Answer(s): (a) 280 kg; (b) 15 : 22