Albert and Pierre have 19 balls altogether. Albert has 7 more balls than Pierre. Find the number of balls each boy has.
- Pierre
- Albert
Number of balls that Pierre has = 1 u
Number of balls that Albert has = 1 u + 7
Total number of balls
= 1 u + 1 u + 7
= 2 u + 7
2 u + 7 = 19
2 u = 19 - 7 = 12
1 u = 12 ÷ 2 = 6
(a)
Number of balls that Pierre has
= 1 u
= 6
(b)
Number of balls that Albert has
= 1 u + 7
= 6 + 7
= 13
Answer(s): (a) 6; (b) 13
