Pierre and Flynn have 17 balls altogether. Pierre has 3 more balls than Flynn. Find the number of balls each boy has.
- Flynn
- Pierre
Number of balls that Flynn has = 1 u
Number of balls that Pierre has = 1 u + 3
Total number of balls
= 1 u + 1 u + 3
= 2 u + 3
2 u + 3 = 17
2 u = 17 - 3 = 14
1 u = 14 ÷ 2 = 7
(a)
Number of balls that Flynn has
= 1 u
= 7
(b)
Number of balls that Pierre has
= 1 u + 3
= 7 + 3
= 10
Answer(s): (a) 7; (b) 10
