Michael and Eric have 18 beads altogether. Michael has 8 more beads than Eric. Find the number of beads each boy has.
- Eric
- Michael
Number of beads that Eric has = 1 u
Number of beads that Michael has = 1 u + 8
Total number of beads
= 1 u + 1 u + 8
= 2 u + 8
2 u + 8 = 18
2 u = 18 - 8 = 10
1 u = 10 ÷ 2 = 5
(a)
Number of beads that Eric has
= 1 u
= 5
(b)
Number of beads that Michael has
= 1 u + 8
= 5 + 8
= 13
Answer(s): (a) 5; (b) 13
