Xavier and Warren have 3 beads altogether. Xavier has 9 more beads than Warren. Find the number of beads each boy has.
- Warren
- Xavier
Number of beads that Warren has = 1 u
Number of beads that Xavier has = 1 u + 9
Total number of beads
= 1 u + 1 u + 9
= 2 u + 9
2 u + 9 = 3
2 u = 3 - 9 = -6
1 u = -6 ÷ 2 = -3
(a)
Number of beads that Warren has
= 1 u
= -3
(b)
Number of beads that Xavier has
= 1 u + 9
= -3 + 9
= 6
Answer(s): (a) -3; (b) 6
