Luke and Eric have 11 balls altogether. Luke has 5 more balls than Eric. Find the number of balls each boy has.
- Eric
- Luke
Number of balls that Eric has = 1 u
Number of balls that Luke has = 1 u + 5
Total number of balls
= 1 u + 1 u + 5
= 2 u + 5
2 u + 5 = 11
2 u = 11 - 5 = 6
1 u = 6 ÷ 2 = 3
(a)
Number of balls that Eric has
= 1 u
= 3
(b)
Number of balls that Luke has
= 1 u + 5
= 3 + 5
= 8
Answer(s): (a) 3; (b) 8
