130 stickers are in 3 bags.
The third bag has 3 times as many stickers as the second bag.
The first bag is 30 less than the second bag.
How many less stickers are there in the second bag and the first bag than in the third bag?
Choose the bag with the least stickers to be 1 u.

Number of stickers in the first bag = 1 u
Number of stickers in the second bag = 1 u + 30
Number of stickers in the third bag = 3 x (1 u + 30) = 3 u + 90

Total number of stickers
= 3 u + 90 + 1 u + 30 + 1 u
= 3 u + 1 u + 1 u + 90 + 30
= 5 u + 120

5 u + 120 = 130
5 u = 130 - 120
5 u = 10

1 u = 10 ÷ 5 = 2

Number of less stickers in the second bag and first bag than the third bag
= (3 u + 90) - (1 u + 30 + 1 u)
= (3 u + 90) - (2 u + 30)
= 3 u - 2 u  + 90 - 30
= 1 u + 60
= 1 x 2 + 60
= 2 + 60
= 62

Answer(s): 62