150 stickers are in 3 bags.
The second bag has 8 times as many stickers as the first bag.
The third bag is 10 less than the first bag.
How many less stickers are there in the first bag and the third bag than in the second bag?
Choose the bag with the least stickers to be 1 u.

Number of stickers in the third bag = 1 u
Number of stickers in the first bag = 1 u + 10
Number of stickers in the second bag = 8 x (1 u + 10) = 8 u + 80

Total number of stickers
= 8 u + 80 + 1 u + 10 + 1 u
= 8 u + 1 u + 1 u + 80 + 10
= 10 u + 90

10 u + 90 = 150
10 u = 150 - 90
10 u = 60

1 u = 60 ÷ 10 = 6

Number of less stickers in the first bag and third bag than the second bag
= (8 u + 80) - (1 u + 10 + 1 u)
= (8 u + 80) - (2 u + 10)
= 8 u - 2 u  + 80 - 10
= 6 u + 70
= 6 x 6 + 70
= 36 + 70
= 106

Answer(s): 106