There are 4 times as many cows as chickens.
There are 180 legs altogether.
- Find the number of animals.
- Find the number of less chickens than cows.
- Find the number of less chickens' legs than cows' legs.
| |
Cows |
Chickens |
Total |
Number
(Number of animals) |
4 u |
1 u |
5 u |
Value
(Number of legs) |
4 |
2 |
|
Total value
(Total number of legs) |
4 x 4 =
16 u |
1 x 2 =
2 u |
18 u |
(a)
Let the number of chickens be 1 u.
Number of cows = 4 u
Number of cows' legs = 4 x 4 u = 16 u
Number of chickens' legs = 2 x 1 u = 2 u
Total number of legs = 16 u + 2 u = 18 u
18 u = 180
1 u = 180 ÷ 18 = 10
Number of animals
= 4 u + 1 u
= 5 u
= 5 x 10
= 50
(b)
Number of less chickens than cows
= 4 u - 1 u
= 3 u
= 3 x 10
= 30
(c)
Number of less chickens' legs than cows' legs
= 16 u - 2 u
= 14 u
= 14 x 10
= 140
Answer(s): (a) 50; (b) 30; (c) 140
