Adam has 2 times as many stickers as Bryan.
After Adam buys another 90 stickers,
he has thrice as many stickers as Bryan.
- How many stickers does Bryan have?
- How many stickers does Adam have in the end?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
2 u |
1 u |
Change |
+ 90 |
No change |
After |
3 u |
1 u |
(a)
The amount that Bryan has at first and in the end remains unchanged.
Make the amount that Bryan has the same using the LCM of 1 and 1.
LCM of 1 and 1 = 1
Number of stickers that Adam buys
= 3 u - 2 u
= 1 u
1 u = 90
Number of stickers that Bryan has
= 1 u
= 90
(b)
Number of stickers that Adam has in the end
= 3 u
= 3 x 90
= 270
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 90
= 270
(d)
Number of stickers that they have in the end
= 3 u + 1 u
= 4 u
= 4 x 90
= 360
Answer(s): (a) 90; (b) 270; (c) 270; (d) 360