Adam has 4 times as many stickers as Bryan.
After Bryan buys another 105 stickers,
he has 2 times as many stickers as Adam.
- How many stickers does Bryan have in the end?
- How many stickers does Adam have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
4 u |
1 u |
Change |
No change |
+ 105 |
After |
4 u |
8 u |
(a)
The amount that Adam has at first and in the end remains unchanged.
Make the amount that Adam has the same using the LCM of 1 and 4.
LCM of 1 and 4 = 4
Number of stickers that Bryan buys
= 8 u - 1 u
= 7 u
7 u = 105
1 u = 105 ÷ 7 = 15
Number of stickers that Bryan has in the end
= 8 u
= 8 x 15
= 120
(b)
Number of stickers that Adam has at first
= 4 u
= 4 x 15
= 60
(c)
Number of stickers that they have at first
= 4 u + 1 u
= 5 u
= 5 x 15
= 75
(d)
Number of stickers that they have in the end
= 4 u + 8 u
= 12 u
= 12 x 15
= 180
Answer(s): (a) 120; (b) 60; (c) 75; (d) 180