Adam has 5 times as many stickers as Bryan.
After Bryan buys another 72 stickers,
he has 2 times as many stickers as Adam.
- How many stickers does Bryan have in the end?
- How many stickers does Adam have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
5 u |
1 u |
Change |
No change |
+ 72 |
After |
5 u |
10 u |
(a)
The amount that Adam has at first and in the end remains unchanged.
Make the amount that Adam has the same using the LCM of 1 and 5.
LCM of 1 and 5 = 5
Number of stickers that Bryan buys
= 10 u - 1 u
= 9 u
9 u = 72
1 u = 72 ÷ 9 = 8
Number of stickers that Bryan has in the end
= 10 u
= 10 x 8
= 80
(b)
Number of stickers that Adam has at first
= 5 u
= 5 x 8
= 40
(c)
Number of stickers that they have at first
= 5 u + 1 u
= 6 u
= 6 x 8
= 48
(d)
Number of stickers that they have in the end
= 5 u + 10 u
= 15 u
= 15 x 8
= 120
Answer(s): (a) 80; (b) 40; (c) 48; (d) 120