Charlie has 5 times as many stickers as Adam.
After Adam buys another 99 stickers,
he has 2 times as many stickers as Charlie.
- How many stickers does Adam have in the end?
- How many stickers does Charlie have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Adam |
Before |
5 u |
1 u |
Change |
No change |
+ 99 |
After |
5 u |
10 u |
(a)
The amount that Charlie has at first and in the end remains unchanged.
Make the amount that Charlie has the same using the LCM of 1 and 5.
LCM of 1 and 5 = 5
Number of stickers that Adam buys
= 10 u - 1 u
= 9 u
9 u = 99
1 u = 99 ÷ 9 = 11
Number of stickers that Adam has in the end
= 10 u
= 10 x 11
= 110
(b)
Number of stickers that Charlie has at first
= 5 u
= 5 x 11
= 55
(c)
Number of stickers that they have at first
= 5 u + 1 u
= 6 u
= 6 x 11
= 66
(d)
Number of stickers that they have in the end
= 5 u + 10 u
= 15 u
= 15 x 11
= 165
Answer(s): (a) 110; (b) 55; (c) 66; (d) 165