Charlie has 2 times as many stickers as Bryan.
After Bryan buys another 84 stickers,
he has 4 times as many stickers as Charlie.
- How many stickers does Bryan have in the end?
- How many stickers does Charlie have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Bryan |
Before |
2 u |
1 u |
Change |
No change |
+ 84 |
After |
2 u |
8 u |
(a)
The amount that Charlie has at first and in the end remains unchanged.
Make the amount that Charlie has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Bryan buys
= 8 u - 1 u
= 7 u
7 u = 84
1 u = 84 ÷ 7 = 12
Number of stickers that Bryan has in the end
= 8 u
= 8 x 12
= 96
(b)
Number of stickers that Charlie has at first
= 2 u
= 2 x 12
= 24
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 12
= 36
(d)
Number of stickers that they have in the end
= 2 u + 8 u
= 10 u
= 10 x 12
= 120
Answer(s): (a) 96; (b) 24; (c) 36; (d) 120