Adam has 2 times as many stickers as Charlie.
After Charlie buys another 40 stickers,
he has 3 times as many stickers as Adam.
- How many stickers does Charlie have in the end?
- How many stickers does Adam have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Charlie |
Before |
2 u |
1 u |
Change |
No change |
+ 40 |
After |
2 u |
6 u |
(a)
The amount that Adam has at first and in the end remains unchanged.
Make the amount that Adam has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Charlie buys
= 6 u - 1 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Number of stickers that Charlie has in the end
= 6 u
= 6 x 8
= 48
(b)
Number of stickers that Adam has at first
= 2 u
= 2 x 8
= 16
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 8
= 24
(d)
Number of stickers that they have in the end
= 2 u + 6 u
= 8 u
= 8 x 8
= 64
Answer(s): (a) 48; (b) 16; (c) 24; (d) 64