Adam has 2 times as many stickers as Bryan.
After Bryan buys another 108 stickers,
he has 5 times as many stickers as Adam.
- How many stickers does Bryan have in the end?
- How many stickers does Adam have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
2 u |
1 u |
Change |
No change |
+ 108 |
After |
2 u |
10 u |
(a)
The amount that Adam has at first and in the end remains unchanged.
Make the amount that Adam has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Bryan buys
= 10 u - 1 u
= 9 u
9 u = 108
1 u = 108 ÷ 9 = 12
Number of stickers that Bryan has in the end
= 10 u
= 10 x 12
= 120
(b)
Number of stickers that Adam has at first
= 2 u
= 2 x 12
= 24
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 12
= 36
(d)
Number of stickers that they have in the end
= 2 u + 10 u
= 12 u
= 12 x 12
= 144
Answer(s): (a) 120; (b) 24; (c) 36; (d) 144