Bryan has 2 times as many stickers as Adam.
After Adam buys another 70 stickers,
he has 4 times as many stickers as Bryan.
- How many stickers does Adam have in the end?
- How many stickers does Bryan have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Bryan |
Adam |
Before |
2 u |
1 u |
Change |
No change |
+ 70 |
After |
2 u |
8 u |
(a)
The amount that Bryan has at first and in the end remains unchanged.
Make the amount that Bryan has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Adam buys
= 8 u - 1 u
= 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Number of stickers that Adam has in the end
= 8 u
= 8 x 10
= 80
(b)
Number of stickers that Bryan has at first
= 2 u
= 2 x 10
= 20
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 10
= 30
(d)
Number of stickers that they have in the end
= 2 u + 8 u
= 10 u
= 10 x 10
= 100
Answer(s): (a) 80; (b) 20; (c) 30; (d) 100