Bryan has 2 times as many stickers as Charlie.
After Charlie buys another 50 stickers,
he has 3 times as many stickers as Bryan.
- How many stickers does Charlie have in the end?
- How many stickers does Bryan have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
| |
Bryan |
Charlie |
| Before |
2 u |
1 u |
| Change |
No change |
+ 50 |
| After |
2 u |
6 u |
(a)
The amount that Bryan has at first and in the end remains unchanged.
Make the amount that Bryan has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Charlie buys
= 6 u - 1 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Number of stickers that Charlie has in the end
= 6 u
= 6 x 10
= 60
(b)
Number of stickers that Bryan has at first
= 2 u
= 2 x 10
= 20
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 10
= 30
(d)
Number of stickers that they have in the end
= 2 u + 6 u
= 8 u
= 8 x 10
= 80
Answer(s): (a) 60; (b) 20; (c) 30; (d) 80
