Adam has 2 times as many stickers as Bryan.
After Bryan buys another 36 stickers,
he has 2 times as many stickers as Adam.
- How many stickers does Bryan have in the end?
- How many stickers does Adam have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Adam |
Bryan |
Before |
2 u |
1 u |
Change |
No change |
+ 36 |
After |
2 u |
4 u |
(a)
The amount that Adam has at first and in the end remains unchanged.
Make the amount that Adam has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Bryan buys
= 4 u - 1 u
= 3 u
3 u = 36
1 u = 36 ÷ 3 = 12
Number of stickers that Bryan has in the end
= 4 u
= 4 x 12
= 48
(b)
Number of stickers that Adam has at first
= 2 u
= 2 x 12
= 24
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 12
= 36
(d)
Number of stickers that they have in the end
= 2 u + 4 u
= 6 u
= 6 x 12
= 72
Answer(s): (a) 48; (b) 24; (c) 36; (d) 72