Charlie has 2 times as many stickers as Bryan.
After Bryan buys another 72 stickers,
he has 5 times as many stickers as Charlie.
- How many stickers does Bryan have in the end?
- How many stickers does Charlie have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
| |
Charlie |
Bryan |
| Before |
2 u |
1 u |
| Change |
No change |
+ 72 |
| After |
2 u |
10 u |
(a)
The amount that Charlie has at first and in the end remains unchanged.
Make the amount that Charlie has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Bryan buys
= 10 u - 1 u
= 9 u
9 u = 72
1 u = 72 ÷ 9 = 8
Number of stickers that Bryan has in the end
= 10 u
= 10 x 8
= 80
(b)
Number of stickers that Charlie has at first
= 2 u
= 2 x 8
= 16
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 8
= 24
(d)
Number of stickers that they have in the end
= 2 u + 10 u
= 12 u
= 12 x 8
= 96
Answer(s): (a) 80; (b) 16; (c) 24; (d) 96
