Charlie has 2 times as many stickers as Adam.
After Adam buys another 33 stickers,
he has 2 times as many stickers as Charlie.
- How many stickers does Adam have in the end?
- How many stickers does Charlie have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
|
Charlie |
Adam |
Before |
2 u |
1 u |
Change |
No change |
+ 33 |
After |
2 u |
4 u |
(a)
The amount that Charlie has at first and in the end remains unchanged.
Make the amount that Charlie has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Adam buys
= 4 u - 1 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Number of stickers that Adam has in the end
= 4 u
= 4 x 11
= 44
(b)
Number of stickers that Charlie has at first
= 2 u
= 2 x 11
= 22
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 11
= 33
(d)
Number of stickers that they have in the end
= 2 u + 4 u
= 6 u
= 6 x 11
= 66
Answer(s): (a) 44; (b) 22; (c) 33; (d) 66