Adam has 2 times as many stickers as Charlie.
After Charlie buys another 42 stickers,
he has 2 times as many stickers as Adam.
- How many stickers does Charlie have in the end?
- How many stickers does Adam have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
| |
Adam |
Charlie |
| Before |
2 u |
1 u |
| Change |
No change |
+ 42 |
| After |
2 u |
4 u |
(a)
The amount that Adam has at first and in the end remains unchanged.
Make the amount that Adam has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Charlie buys
= 4 u - 1 u
= 3 u
3 u = 42
1 u = 42 ÷ 3 = 14
Number of stickers that Charlie has in the end
= 4 u
= 4 x 14
= 56
(b)
Number of stickers that Adam has at first
= 2 u
= 2 x 14
= 28
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 14
= 42
(d)
Number of stickers that they have in the end
= 2 u + 4 u
= 6 u
= 6 x 14
= 84
Answer(s): (a) 56; (b) 28; (c) 42; (d) 84
