Charlie has 4 times as many stickers as Adam.
After Adam buys another 77 stickers,
he has 2 times as many stickers as Charlie.
- How many stickers does Adam have in the end?
- How many stickers does Charlie have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
| |
Charlie |
Adam |
| Before |
4 u |
1 u |
| Change |
No change |
+ 77 |
| After |
4 u |
8 u |
(a)
The amount that Charlie has at first and in the end remains unchanged.
Make the amount that Charlie has the same using the LCM of 1 and 4.
LCM of 1 and 4 = 4
Number of stickers that Adam buys
= 8 u - 1 u
= 7 u
7 u = 77
1 u = 77 ÷ 7 = 11
Number of stickers that Adam has in the end
= 8 u
= 8 x 11
= 88
(b)
Number of stickers that Charlie has at first
= 4 u
= 4 x 11
= 44
(c)
Number of stickers that they have at first
= 4 u + 1 u
= 5 u
= 5 x 11
= 55
(d)
Number of stickers that they have in the end
= 4 u + 8 u
= 12 u
= 12 x 11
= 132
Answer(s): (a) 88; (b) 44; (c) 55; (d) 132
