Bryan has 2 times as many stickers as Adam.
After Adam buys another 135 stickers,
he has 5 times as many stickers as Bryan.
- How many stickers does Adam have in the end?
- How many stickers does Bryan have?
- How many stickers do they have at first?
- How many stickers do they have in the end?
| |
Bryan |
Adam |
| Before |
2 u |
1 u |
| Change |
No change |
+ 135 |
| After |
2 u |
10 u |
(a)
The amount that Bryan has at first and in the end remains unchanged.
Make the amount that Bryan has the same using the LCM of 1 and 2.
LCM of 1 and 2 = 2
Number of stickers that Adam buys
= 10 u - 1 u
= 9 u
9 u = 135
1 u = 135 ÷ 9 = 15
Number of stickers that Adam has in the end
= 10 u
= 10 x 15
= 150
(b)
Number of stickers that Bryan has at first
= 2 u
= 2 x 15
= 30
(c)
Number of stickers that they have at first
= 2 u + 1 u
= 3 u
= 3 x 15
= 45
(d)
Number of stickers that they have in the end
= 2 u + 10 u
= 12 u
= 12 x 15
= 180
Answer(s): (a) 150; (b) 30; (c) 45; (d) 180
